8.5 Definite and Indefinite Integrals

Integration is the reverse process of differentiation and is used to find areas under curves, accumulated quantities, and antiderivatives.

Key Concepts:

Examples:

Example 1: Indefinite Integral

Evaluate: \[ \int (3x^2 + 4x - 5) \,dx \]

Solution:

\[ \int (3x^2 + 4x - 5) \,dx = \frac{3x^3}{3} + \frac{4x^2}{2} - 5x + C \] \[ = x^3 + 2x^2 - 5x + C \] Thus, the answer is \( \boxed{x^3 + 2x^2 - 5x + C} \).

Example 2: Definite Integral

Evaluate: \[ \int_1^3 (2x + 1) \,dx \]

Solution:

Find the antiderivative: \[ \int (2x + 1) \,dx = x^2 + x \] Evaluate at the limits: \[ F(3) = 3^2 + 3 = 9 + 3 = 12, \quad F(1) = 1^2 + 1 = 1 + 1 = 2 \] \[ \int_1^3 (2x + 1) \,dx = 12 - 2 = 10 \] Thus, the answer is \( \boxed{10} \).

Example 3: Finding Area Under a Curve

Find the area under \( f(x) = x^2 \) from \( x = 0 \) to \( x = 2 \).

Solution:

\[ \int_0^2 x^2 \,dx = \frac{x^3}{3} \Big|_0^2 \] Evaluate at the limits: \[ \frac{2^3}{3} - \frac{0^3}{3} = \frac{8}{3} - 0 = \frac{8}{3} \] Thus, the area under the curve is \( \boxed{\frac{8}{3}} \).

Section 8: Miscellaneous Topics

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